4.9x^2+3.14x-2=0

Solution for 4.9x^2+3.14x-2=0 equation:

4.9x^2+3.14x-2=0

a = 4.9; b = 3.14; c = -2;
Δ = b2-4ac
Δ = 3.142-4·4.9·(-2)
Δ = 49.0596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.14)-\sqrt{49.0596}}{2*4.9}=\frac{-3.14-\sqrt{49.0596}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.14)+\sqrt{49.0596}}{2*4.9}=\frac{-3.14+\sqrt{49.0596}}{9.8}
$